package Base_se.Base_701;

import java.util.Scanner;

/**
 * @author gyf
 * @ClassName test
 * @Date 2024/7/1 19:57
 * @Version V1.0
 * @Description : 数字加密
 * 某系统的数字密码(大于0)，比如1983，采用加密方式进行传输。
 * 规则如下: 先得到每位数，然后每位数都加上5，再对10求余，最后将所有数字反转，得到一串新数
 */
public class Solution {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        int number = scanner.nextInt();
        int temp = number;
        int index = 0;
        int cout = 0;

        // 判断输入值
        while (true) {
            if (number <= 0) {
                System.out.println("输入有误,重新输入:");
                number = scanner.nextInt();
            } else {
                System.out.println("输入正确");
                break;
            }
        }

        System.out.println("输入的值:" + number);
        // 获得位数
        while (number != 0) {
            number = number / 10;
            cout++;
        }
        System.out.println(cout);
        // 初始化数组
        int[] arr = new int[cout];


        while (temp != 0) {
            int ge = temp % 10;
            // 去掉右边一位数字
            temp = temp / 10;
            arr[index] = ge;
            index++;
        }
        for (int i = 0; i < arr.length; i++) {
            arr[i] = getReverse(arr[i]);
        }
        for (int i = 0; i < arr.length; i++) {
            System.out.println(arr[i]);
        }

    }

    public static int getReverse(int num) {
        int newNumber = (num + 5) % 10;
        return newNumber;
    }
}